226. Invert Binary Tree
4
/ \
2 7
/ \ / \
1 3 6 9 4
/ \
7 2
/ \ / \
9 6 3 1# Definition for a binary tree node.
# class TreeNode
# attr_accessor :val, :left, :right
# def initialize(val = 0, left = nil, right = nil)
# @val = val
# @left = left
# @right = right
# end
# end
# @param {TreeNode} root
# @return {TreeNode}
def invert_tree(root)
return if !root
root.right, root.left = root.left, root.right
invert_tree(root.left)
invert_tree(root.right)
root
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