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Leetcode
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    • 1. Two Sum
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  • C#
    • 1. Two Sum
    • 7. Reverse Integer
    • 9. Palindrome Number
    • 13. Roman to Integer
    • 14. Longest Common Prefix
    • 20. Valid Parentheses
    • 21. Merge Two Sorted Lists
    • 26. Remove Duplicates from Sorted Array
    • 27. Remove Element
    • 28. Implement strStr()
    • 35. Search Insert Position
    • 38. Count and Say
    • 53. Maximum Subarray
    • 58. Length of Last Word
    • 191. Number of 1 Bits
    • 231. Power of Two
    • 401. Binary Watch
    • 1114. Print in Order
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  1. C#

1. Two Sum

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

You can return the answer in any order.

Example 1:

Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Output: Because nums[0] + nums[1] == 9, we return [0, 1].

Example 2:

Input: nums = [3,2,4], target = 6
Output: [1,2]

Example 3:

Input: nums = [3,3], target = 6
Output: [0,1]

Constraints:

  • 2 <= nums.length <= 103

  • -109 <= nums[i] <= 109

  • -109 <= target <= 109

  • Only one valid answer exists.

public class Solution {
    public int[] TwoSum(int[] nums, int target) {
      
      Hashtable h_table = new Hashtable();
      
      for(int i = 0; i < nums.Length; i++){
        if(h_table.ContainsKey(target - nums[i])){
          return new int[2] {(int)h_table[target - nums[i]], i};
        }
        else if(!h_table.ContainsKey(nums[i])){
          h_table.Add(nums[i],i);
        }
      }
      return new int[2];
    }
}
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