7. Reverse Integer

Given a 32-bit signed integer, reverse digits of an integer.

Note: Assume we are dealing with an environment that could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

Example 1:

Input: x = 123
Output: 321

Example 2:

Input: x = -123
Output: -321

Example 3:

Input: x = 120
Output: 21

Example 4:

Input: x = 0
Output: 0

Constraints:

• -231 <= x <= 231 - 1

public class Solution {
    public int Reverse(int x) {
      if(x == 0){
        return 0;
      }
      string new_string = NewString(x);
      int new_int = Conver(new_string);
      if(new_int == 0){
        return 0;
      }
      if(x < 0){
        return (-new_int) < Int32.MinValue ? 0 : (-new_int);
      }
      else{
        return new_int > Int32.MaxValue ? 0 : new_int;
      }
    }
  
    public string NewString(int x){
      string orgin = x.ToString();
      char[] c = orgin.ToCharArray();
      if(x < 0){
        c = c.Skip(1).ToArray();
      }
      Array.Reverse(c);
      string new_s = new String(c);
      return new_s;
    }
  
    public int Conver(string x){
      int new_x;
      bool isParse = Int32.TryParse(x, out new_x);
      if(isParse){
        return new_x;
      }
      return 0;
    }
}