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Leetcode
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    • 1. Two Sum
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    • 141. Linked List Cycle
    • 155. Min Stack
    • 160. Intersection of Two Linked Lists
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    • 203. Remove Linked List Elements
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  • C#
    • 1. Two Sum
    • 7. Reverse Integer
    • 9. Palindrome Number
    • 13. Roman to Integer
    • 14. Longest Common Prefix
    • 20. Valid Parentheses
    • 21. Merge Two Sorted Lists
    • 26. Remove Duplicates from Sorted Array
    • 27. Remove Element
    • 28. Implement strStr()
    • 35. Search Insert Position
    • 38. Count and Say
    • 53. Maximum Subarray
    • 58. Length of Last Word
    • 191. Number of 1 Bits
    • 231. Power of Two
    • 401. Binary Watch
    • 1114. Print in Order
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  1. Ruby

198. House Robber

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

Example 1:

Input: nums = [1,2,3,1]
Output: 4
Explanation: Rob house 1 (money = 1) and then rob house 3 (money = 3).
             Total amount you can rob = 1 + 3 = 4.

Example 2:

Input: nums = [2,7,9,3,1]
Output: 12
Explanation: Rob house 1 (money = 2), rob house 3 (money = 9) and rob house 5 (money = 1).
             Total amount you can rob = 2 + 9 + 1 = 12.

Constraints:

  • 0 <= nums.length <= 100

  • 0 <= nums[i] <= 400

# @param {Integer[]} nums
# @return {Integer}
def rob(nums)
  odd_pos = 0
  even_pos = 0
  for i in 0...nums.length
    if i.even?
      even_pos = [even_pos + nums[i], odd_pos].max
    elsif i.odd?
      odd_pos = [odd_pos + nums[i], even_pos].max      
    end
  end
  [odd_pos, even_pos].max
end
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Last updated 4 years ago

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