# 231. Power of Two

Given an integer `n`, return *`true` if it is a power of two. Otherwise, return `false`*.

An integer `n` is a power of two, if there exists an integer `x` such that `n == 2x`.

**Example 1:**

```
Input: n = 1
Output: true
Explanation: 20 = 1
```

**Example 2:**

```
Input: n = 16
Output: true
Explanation: 24 = 16
```

**Example 3:**

```
Input: n = 3
Output: false
```

**Example 4:**

```
Input: n = 4
Output: true
```

**Example 5:**

```
Input: n = 5
Output: false
```

**Constraints:**

* `-231 <= n <= 231 - 1`

&#x20;**Follow up:** Could you solve it without loops/recursion?

```
# @param {Integer} n
# @return {Boolean}

def is_power_of_two(n)
  return false if n <= 0
  return true if n == 1
  n.to_s(2).count('1') == 1 ? true : false
end
```
